Work function of a metal is 2.1 eV. Which of the waves of the following wavelengths will be able to emit photoelectrons from its surface

$4000 \circ A, 7500 \circ A$

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$5500 \circ A, 6000 \circ A$

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$4000 \circ A, 6000 \circ A$

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$N o n e o f t h e s e$

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Solution

The correct option is D
$N o n e o f t h e s e$

Threshold wavelength $λ_{0} = \frac{12375}{2.1} = 5892.8 \circ A$

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