Work function of a metal is 3-0eV- It is illuminated by a light of wavelength 3 - 10-7m- Then the maximum energy of the electron is-

The correct option is C 1.13 eV Maximum energy =hcλ ϕ #160; (3× 10^ 7m=300nm) =1240300 3 (hc = #160; 1240 eV / X nm) =4.13 3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Huygens' Principle

Work function...

Question

Work function of a metal is 3.0eV. It is illuminated by a light of wavelength $3 \times 10^{- 7}$ m. Then the maximum energy of the electron is.

2.34 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.85 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.13 e V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.32 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $1.13 e V$
$M a x i m u m e n e r g y = \frac{h c}{λ} - ϕ (3 \times 10^{- 7} m = 300 n m)$
$= \frac{1240}{300} - 3 (h c = 1240 e V / X n m)$
$= 4.13 - 3$
$= 1.13 e V .$
So, the answer is option (C).

Suggest Corrections

Similar questions

Q. The work function of a metal is 3.0eV. It is illuminated by a light of wave length

3 \times 10^{- 7} m

. then
i) Threshold frequency
ii) maximum energy of photoelectrons,
iii) the stopping potential.

(

h = 6.63 \times 10^{- 34} m

Js and

c = 3 \times 10^{8} m / s

)

The work function of a metal is $1.6 \times 10^{- 19} J$ . When the metal surface is illuminated by the light of wavelength $6400 \circ A$ , then the maximum kinetic energy of emitted photo-electrons will be (Planck's constant $h = 6.4 \times 10^{- 34} J s$ )

Q. The work function of a metal is

1.6 \times 10^{- 19}

J. When the metal surface is illuminated by the light of wavelength 6400

A^{o}

, then the maximum kinetic energy of emitted photoelectrons will be (

h = 6.4 \times 10^{- 34} J s

)

Q. The work function of a metal is

1.6 \times 10^{- 19} J .

When the metal surface is illuminated by the light of wavelength 6400 Å, then the maximum kinetic energy of emitted photo-electrons will be
(Planck's constant h =

6.4 \times 10^{- 34} J s)

Q. A metal whose work function is

3.3 e V

is illuminated by light of wavelength

3 \times 10^{- 7}

m. What is the threshold frequency for photoelectric emission? Given Planck's constant

= 6.6 \times 10^{- 34} J s

Join BYJU'S Learning Program

Work function of a metal is 3.0eV. It is illuminated by a light of wavelength 3×10−7m. Then the maximum energy of the electron is.

The correct option is C 1.13 eVMaximum energy=hcλ−ϕ(3×10−7m=300nm)=1240300−3 (hc=1240 eV/Xnm)=4.13−3=1.13eV.So, the answer is option (C).

Work function of a metal is 3.0eV. It is illuminated by a light of wavelength $3 \times 10^{- 7}$ m. Then the maximum energy of the electron is.

The correct option is C $1.13 e V$
$M a x i m u m e n e r g y = \frac{h c}{λ} - ϕ (3 \times 10^{- 7} m = 300 n m)$
$= \frac{1240}{300} - 3 (h c = 1240 e V / X n m)$
$= 4.13 - 3$
$= 1.13 e V .$
So, the answer is option (C).