Work function of $A l$ is $4.2 e V$ . If two photons, each of energy $2.5 e V$ are incident on its surface, will the emission of electrons take place? Justify your answer.

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Solution

Given that ;
Work function of $A l, ϕ = 4.2 e V$
The energy of each incident photon, $E$
$E = 2.5 e V$
As we know, one photon can eject one electron only. The emission of electrons will take place only when the minimum energy of the incident photon will be equal to the work function of the metal.
Here, the energy of each photon $(E = 2.5 e V)$ is less than the work function of aluminum.
So, the emission will not take place.

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