Work of 3.0×10−4 joule is required to be done in increasing the size of a soap film from 10cm×6cm to 10cm×11cm. The surface tension of the film is
A
5×10−2N/m
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B
3×10−2N/m
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C
1.5×10−2N/m
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D
1.2×10−2N/m
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Solution
The correct option is B3×10−2N/m Surface tension, S=Work doneIncrease in area As the soap film has two surfaces. S=3.0×10−4J2×(10×11−10×6)×10−4m2=3×10−2N/m. Hence, the correct answer is option (b).