Work of $490 J$ is done on a load of mass $5 k g$ to lift it to a certain height. calculate the height through which the load is lifted.

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Solution

Step 1: Data provided,
$W o r k (W) = 490 J M a s s (m) = 5 k g$
Step 2: Formula used,
$W o r k d o n e = F o r c e \times d i s p l a c e m e n t F o r c e = M a s s \times a c c e l e r a t i o n$
Step 3: Calculation,
$T h e m i n i m u m f o r c e r e q u i r e d t o l i f t t h e b o d y o f m a s s m u p w a r d (F) = m g W o r k = f o r c e \times D i s p l a c e m e n t = m g \times h o r, W = m g h \Rightarrow h = \frac{W}{m g} = \frac{490}{5 \times 9.8} m = \frac{490}{49} m = 10 m$
Hence, the height of the object is $10 m$

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Work of 490J is done on a load of mass 5kg to lift it to a certain height. calculate the height through which the load is lifted.

Step 1: Data provided,Work(W)=490JMass(m)=5kgStep 2: Formula used,Workdone=Force×displacementForce=Mass×accelerationStep 3: Calculation,Theminimumforcerequiredtoliftthebodyofmassmupward(F)=mgWork=force×Displacement=mg×hor,W=mgh⇒h=Wmg=4905×9.8m=49049m=10mHence, the height of the object is 10m

Work of $490 J$ is done on a load of mass $5 k g$ to lift it to a certain height. calculate the height through which the load is lifted.