Question

Work out a positive solution of the following equation:

$x^2+x=6$.

Answer 1

Now,

$x^2+x=6$

or, $x^2+x-6=0$

or, $x^2+3x-2x-6=0$

or, $x(x+3)-2(x+3)=0$

or, $(x+3)(x-2)=0$

or, $x=-3,2$.

So a positive root is $2$.