Question

Work out the following division: $10y(6y+21)÷5(2y+7)$.

Answer 1

Divide $10y(6y+21)÷5(2y+7)$.

Cancel out the common factors.

$\begin{array}{rcl}10y(6y+21)÷5(2y+7)& =& \frac{10y(6y+21)}{5(2y+7)}\\ & =& \frac{10y\times 3(2y+7)}{5(2y+7)}\\ & =& \frac{10y\times 3}{5}\\ & =& 6y\end{array}$

Thus, the quotient for given division is $6y$.