Question

Work out the following division: $9x^2{y}^2(3z-24)÷27xy(z-8)$.

Answer 1

Solution.

$$\begin{gathered} \frac{9x^2{y}^2(3z-24)}{27xy(z-8)}=\frac{9x^2{y}^2\times 3(z-8)}{27xy(z-8)} \\ =\frac{27x^2{y}^2}{27xy} \\ =xy \end{gathered}$$

Thus, $9x^2{y}^2(3z-24)÷27xy(z-8)=xy$