Question

Work out the following divisions.

$96abc(3a-12)(5b+30)÷144(a-4)(b+6)$

• A. $96abc$
• B. $10abc$
• C. $144abc(b-12)$
• D. $24(a-b+c)$

Answer 1

The correct option is B $10abc$

$96abc(3a-12)(5b+30)÷144(a-4)(b+6)$
$=\frac{96abc(3a-12)(5b+30)}{144(a-4)(b+6)}$
$=\frac{2\times 2\times 2\times 2\times 2\times 3abc\times 3(a-4)\times 5(b+6)}{2\times 2\times 2\times 2\times 3\times 3(a-4)(b+6)}$
$=10abc$