Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same job. How long should it take both A and B, working together but independently, to do the same job?

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Solution

The correct option is A

A’s 1 hour’s work = $\frac{1}{8}$

B’s 1 hour’s work = $\frac{1}{10}$

(A+B)’s 1 hour’s work = $(\frac{1}{8} + \frac{1}{10}) = \frac{9}{40}$

∴ Both A and B will finish the work in $\frac{40}{9} h o u r s .$

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Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same job. How long should it take both A and B, working together but independently, to do the same job?

The correct option is A A’s 1 hour’s work = 18 B’s 1 hour’s work = 110 (A+B)’s 1 hour’s work = (18+110)=940 ∴ Both A and B will finish the work in 409hours.

The correct option is A

A’s 1 hour’s work = $\frac{1}{8}$

B’s 1 hour’s work = $\frac{1}{10}$

(A+B)’s 1 hour’s work = $(\frac{1}{8} + \frac{1}{10}) = \frac{9}{40}$

∴ Both A and B will finish the work in $\frac{40}{9} h o u r s .$