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Question

Write -1 + i 3 in polar form.

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Solution

Let z = -1 + i 3

Modulus, |z|=(1)2+(3)2=4=2Argument, θ=tan1(31)=tan1(3)=ππ3=2π3Polar Form,2[cos(2π3)+i sin(2π3)]=2[cos(2π3)+i sin(2π3)]


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