Write $3^{12}, 2^{15}, 5^{6}$ in the ascending order.

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Solution

Now,
$3^{12} = (3^{4})^{3} = (81)^{3}$ , $2^{15} = (2^{5})^{3} = (32)^{3}$ and $5^{6} = (5^{2})^{3} = (25)^{3}$ .
Since $(81)^{3} > (32)^{3} > (25)^{3}$ so $3^{12} > 2^{15} > 5^{6}$ .

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