Write 47 as the sum of powers of 2

$2^{5} + 2^{3} + 2^{7} + 2^{1} + 1$

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$2^{5} + 2^{4} + 2^{2} + 2^{1} + 1$

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$2^{5} + 2^{3} + 2^{2} + 2^{1} + 3$

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$2^{5} + 2^{3} + 2^{2} + 2^{1} + 1$

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Solution

The correct option is D
$2^{5} + 2^{3} + 2^{2} + 2^{1} + 1$

47=32+8+4+2+1

$47 = 2^{5} + 2^{3} + 2^{2} + 2^{1} + 1$

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A positive integer is called "Panache” if it can be written as a sum of distinct positive powers of 4, and "Elan" if it can be written as a sum of distinct positive powers of 6. From the given number, which of the following can we write as a sum of a "Panache” number and an "Elan" number?

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Write 47 as the sum of powers of 2

The correct option is D 25+23+22+21+1 47=32+8+4+2+1 47=25+23+22+21+1

The correct option is D
$2^{5} + 2^{3} + 2^{2} + 2^{1} + 1$

47=32+8+4+2+1

$47 = 2^{5} + 2^{3} + 2^{2} + 2^{1} + 1$