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Question

Write 6y3−4y8+2y5−7y9 in standard form.

A
7y94y8+2y5+6y3
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B
7y9+6y34y8+2y5
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C
6y3+2y54y87y9
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D
2y54y8+6y37y9
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Solution

The correct option is A 7y94y8+2y5+6y3
Standard Form of a Polynomial:––––––––––––––––––––––––––––––––––––––
A polynomial is said to be in its standard form, if it is expressed in such a way that the term with the highest degree is placed first, followed by the term which has the next highest degree, and so on.

We are given with a polynomial expression 6y34y8+2y57y9

The highest exponent of this polynomial is 9 and the corresponding term is 7y9.

The second highest exponent is 8 and the corresponding term is 4y8.

The third highest exponent is 5 and the corresponding term is 2y5.

The fourth highest exponent is 3 and the corresponding term is 6y3.

Now, arranging the exponents in descending order, we get the standard form of polynomial as:
7y94y8+2y5+6y3

Therefore, option (a.) is the correct answer.

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