Write $\sqrt{7} y = 2 x$ as a linear equation of the form ax + by + c = 0. Also, write the values corresponding to a, b, c. Does the graph of this linear equation pass through origin? Give your answer in 'yes' or 'no'.

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Solution

$We have, \sqrt{7} y = 2 x \Rightarrow 2 x - \sqrt{7} y + 0 = 0 So, a = 2, b = - \sqrt{7} and c = 0 Also, If x = 0, then \sqrt{7} y = 2 (0) \Rightarrow \sqrt{7} y = 0 \Rightarrow y = \frac{0}{\sqrt{7}} \Rightarrow y = 0$

Yes, the graph of the given linear equation passes through origin.

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Write 7y = 2x as a linear equation of the form ax + by + c = 0. Also, write the values corresponding to a, b, c. Does the graph of this linear equation pass through origin? Give your answer in 'yes' or 'no'.

We have,7y=2x⇒2x-7y+0=0So, a=2, b=-7 and c=0Also,If x=0, then7y=20⇒7y=0⇒y=07⇒y=0 Yes, the graph of the given linear equation passes through origin.

Write $\sqrt{7} y = 2 x$ as a linear equation of the form ax + by + c = 0. Also, write the values corresponding to a, b, c. Does the graph of this linear equation pass through origin? Give your answer in 'yes' or 'no'.

$We have, \sqrt{7} y = 2 x \Rightarrow 2 x - \sqrt{7} y + 0 = 0 So, a = 2, b = - \sqrt{7} and c = 0 Also, If x = 0, then \sqrt{7} y = 2 (0) \Rightarrow \sqrt{7} y = 0 \Rightarrow y = \frac{0}{\sqrt{7}} \Rightarrow y = 0$

Yes, the graph of the given linear equation passes through origin.