Question

Write a balanced chemical equation for and also CLASSIFY THEM:
(A) Lead acetate solution is treated with dilute hydrochloric acid to form lead chloride and acetic acid solution.
(B)A piece of sodium metal is added to absolute ethanol to form sodium ethoxide and hydrogen gas.
(C) Hydrogen sulphide reacts with oxygen gas to form solid sulphur and liquid water.

Answer 1

The solution is as follows:

1. (CH₃COO)₂Pb (aq) + 2 HCl (aq) $\to$ PbCl_​2(s) + 2 CH₃COOH (aq)

Double displacement reaction.

2. 2 Na (s) + 2 C₂H₅OH (aq) $\to$ 2 C₂H₅ONa (aq) + H₂(g)

Displacement reaction

3. 8 H₂S (g) + 4 O₂ (g) $\to$ 8 H₂O(l) + S₈ (s)

Displacement reaction.