Question

Write a balanced chemical equation for the following:

Action of dilute Sulphuric acid on Sodium hydroxide.

Answer 1

When dilute Sulphuric acid $\left(H_2{\mathrm{SO}}_4\right)$ reacts with Sodium hydroxide$\left(\mathrm{NaOH}\right)$, it gives Sodium sulphate$\mathbf{\left(}{\mathbf{Na}}_{\mathbf{2}}{\mathbf{SO}}_{\mathbf{4}}\mathbf{\right)}$ and Water as a product.

Balanced chemical equation:

$\underset{\mathrm{Sodium}\mathrm{hydroxide}}{\underbrace{2\mathrm{NaOH}\left(\mathrm{aq}\right)}}+\underset{\mathrm{Sulphuric}\mathrm{acid}}{\underbrace{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}}\to \underset{\mathrm{Sodium}\mathrm{sulphate}}{\underbrace{{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}}+\underset{\mathrm{Water}}{\underbrace{2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}}$