Write a balanced equation for the reaction of red lead (trilead tetroxide) warmed with conc. HCI.

{2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{P b}_{3} O_{4} + 16 H C l \to 3 P b C l + {8 H}_{2} O + {5 C l}_{2}

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{2 P b}_{3} O_{4} + 8 H C l \to 6 P b C l + {4 H}_{2} O + {5 C l}_{2}

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{2 P b}_{3} O_{4} + 8 H C l \to 6 P b C l + {4 H}_{2} O + {C l}_{2}

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Solution

The correct option is A ${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$
The Balanced reaction is :
${2 P b}_{3} O_{4} + 16 H C l \to 6 P b C l + {8 H}_{2} O + {5 C l}_{2}$

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Similar questions

2 K M n O_{4} + 16 H C l \to 5 C l_{2} + 2 M n C l_{2} + 2 K C l + 8 H_{2} O

K M n O_{4} + H_{2} S O_{4} + H C l \to K_{2} S O_{4} + M n S O_{4} + C l_{2} + H_{2} O

Write balanced equation for the following reaction:
Red lead (trilead tetroxide) is warmed with concentrated hydrochloric acid.

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

H C l

58.4 g

H C l

2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 5 C l_{2} + 8 H_{2} O

H C l

58.4 g

H C l

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