Write a chemical equation for burning of lanthanoids ( $l n$ ) in oxygen.

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Solution

$4 L n + 3 O_{2} \to 2 L n_{2} O_{3}$
Exception :- ce from $c e O_{2}$ instead of $c e_{2} O_{3}$

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Write a chemical equation for burning of lanthanoids (ln) in oxygen.

4Ln+3O2→2Ln2O3Exception :- ce from ceO2 instead of ce2O3

Write a chemical equation for burning of lanthanoids ( $l n$ ) in oxygen.

$4 L n + 3 O_{2} \to 2 L n_{2} O_{3}$
Exception :- ce from $c e O_{2}$ instead of $c e_{2} O_{3}$