Question

Write a chemical equation of the reaction of ethanoic acid with sodium.

Answer 1

The reaction of Ethanoic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$ with Sodium $\left(\mathrm{Na}\right)$ forms Sodium ethanoate $\left({\mathrm{CH}}_3\mathrm{COONa}\right)$ and Hydrogen $\left({\mathrm{H}}_2\right)$ gas as the major product.

Chemical reaction

The chemical equation of the reaction of Ethanoic acid with Sodium is written as:

$$\begin{gathered} 2{\mathrm{CH}}_3\mathrm{COOH}+2\mathrm{Na}\to 2{\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{H}}_2\left(\mathrm{g}\right) \\ \mathrm{Ethanoic}\mathrm{acid}\mathrm{Sodium}\mathrm{ethanoate} \end{gathered}$$