Question

Write a fully balanced equation for each of the following cases.
Red lead is warmed with concentrated hydrochloric acid.

Answer 1

${\mathrm{Pb}}_3{\mathrm{O}}_4\left(\mathrm{s}\right)+8\mathrm{HCl}\left(\mathrm{aq}\right)\to 3{\mathrm{PbCl}}_2\left(\mathrm{s}\right)+4{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+{\mathrm{Cl}}_2\left(\mathrm{g}\right)$
1. Red Lead ($P{b}_3{O}_4$) gives a white precipitate when it reacts with concentrated Hydrochloric acid ($HCl$).
2. This white precipitate dissolves on heating but reappears when cooled.
3. This white precipitate is called Lead Chloride ($PbC{l}_2$).

${\mathrm{Pb}}_3{\mathrm{O}}_4\left(\mathrm{s}\right)+8\mathrm{HCl}\left(\mathrm{aq}\right)\to 3{\mathrm{PbCl}}_2\left(\mathrm{s}\right)+4{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+{\mathrm{Cl}}_2\left(\mathrm{g}\right)$is the balanced equation when red Lead is warmed with concentrated Hydrochloric acid.