Question

Write a Pythagorean triplet whose one member is 6

Answer 1

As we know $2m$, $m^2+1$ and $m^2-1$ from a Pythagorean triplet for any number , m>1
Let us assume 2m=6
Therefore, m =3
And $m^2+1=3^2+1=9+1=10$
And $m^2-1=3^2-1=9-1=8$
Test : $6^2+8^2=36+64=100={10}^2$
Hence the triplet is 6,8, and 10 Answer