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Question

Write a Pythagorean triplet whose smallest number is 14

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Solution

We know that 2m,m2−1 and m2+1 is a Pythagorean triplet where m>1

according to question

smallest number =14
  • means 2m =14

m=14/2=7
  • m²-1= 7²-1

= 49-1= 48
  • m²+1=7²+1

= 49+1=50

hence the required triplet is 14, 48 and 50

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