Question

WRITE A REACTION SHOWING CONVERSION OF ETHANOL TO ETHANOIC ACID . WHY THE REACTION BETWEEN METHANE AND CHLORINE IS CONSIDERED A SUBSTITUION REACTION?

Answer 1

Dear student,
Ethanol can be converted to ethanoic acid by oxidation of ethanol with acidified K₂Cr₂O₇ or alkaline KMnO_​4
$$\begin{gathered} C{H}_{3}C{H}_{2}OH\underset{∆}{\overset{alkalineKMn{O}_4}{\to }}C{H}_{3}COOH \\ C{H}_{3}C{H}_{2}OH\underset{∆}{\overset{acidified{K}_{2}C{r}_2{O}_7}{\to }}C{H}_{3}COOH \end{gathered}$$

Reaction between methane and Chlorine is a free radical substitution reaction because the hydrogens in methane are replaced or sunstituted by the Cl .
$C{H}_4+C{l}_2\stackrel{h\nu }{\to }C{H}_{3}Cl+HCl$
The free radical is a chain reaction and continues till all the H are replaced by Cl
$CHC{l}_3+C{l}_2\stackrel{h\nu }{\to }CC{l}_4$
Regards!