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Question

Write a value of loge x dx.

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Solution

loge x dx
= 1II.loge xI dx
=loge x1 dx-ddxloge x1 dxdx
= loge x 1 . dx – ​ 1x×x.dx
= loge x × x – ​ dx
=​ x loge x – x + C
=​ x loge x – x + C
= x (loge x – 1) + C

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