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B
y=0.075cos(1.05x−2t)
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C
y=0.075sin(1.05x−4πt)
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D
None
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Solution
The correct option is By=0.075cos(1.05x−4πt) Given that, the amplitude is maximum at the end at t = 0. This makes the wave a cos function. From the given data, frequency f = 2Hz wave speed V = 12 m/s Amplitude A = 0.075 m The standard cos wave function is given by y = A cos(kx - Ω t),
where, Ω = Angular frequency = k*V k = wave number = 2 π / wavelength(λ) \lambda = V/f = 6 m k=2π/6=1.051/m Ω = k*V = 12* π/ 3 = 4 π From these values, substituting in the standard equation, we have y = 0.075 cos (1.05x - 4 π t)