Write all the other trigonometric ratios of $∠$ A in terms of $sec A$ .

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Solution

$s e c A = \frac{1}{c o s A}$

$s e c A = \frac{1}{\sqrt{1 - s i n^{2} A}}$

$s e c A = \sqrt{1 + t a n^{2} A}$

$s e c A = \frac{\sqrt{1 + c o t^{2} A}}{c o t A}$

$s e c A = \frac{c o s e c A}{\sqrt{c o s e c^{2} A - 1}}$

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