Question

Write an A.P. whose first term is a and common difference is d in each of the following.
(1) a = 10, d = 5
(2) a = –3, d = 0
(3) a = –7, d = $\frac{1}{2}$
(4) a = –1.25, d = 3
(5) a = 6, d = –3
(6) a = 19, d = –4

Answer 1

(1) a = 10, d = 5

First term = a = 10
Second term = a + d = 10 + 5 = 15
Third term = a + 2d = 10 + 10 = 20
and so on...

Hence, the required A.P. is 10, 15, 20, 25, ...

(2) a = –3, d = 0

First term = a = –3
Second term = a + d = –3 + 0 = –3
Third term = a + 2d = –3 + 0 = –3
and so on...

Hence, the required A.P. is –3, –3, –3, ...

(3) a = –7, d = $\frac{1}{2}$

First term = a = –7
Second term = a + d = $-7+\frac{1}{2}=-\frac{13}{2}$
Third term = a + 2d = –7 + 1 = –6
and so on...

Hence, the required A.P. is –7, –$\frac{13}{2}$, –6, ...

(4) a = –1.25, d = 3

First term = a = –1.25
Second term = a + d = –1.25 + 3 = 1.75
Third term = a + 2d = –1.25 + 6 = 4.75
and so on...

Hence, the required A.P. is –1.25, 1.75, 4.75, ...

(5) a = 6, d = –3

First term = a = 6
Second term = a + d = 6 – 3 = 3
Third term = a + 2d = 6 – 6 = 0
and so on...

Hence, the required A.P. is 6, 3, 0, ...

(6) a = 19, d = –4

First term = a = 19
Second term = a + d = 19 – 4 = 15
Third term = a + 2d = 19 – 8 = 11
and so on...

Hence, the required A.P. is 19, 15, 11, ...