Question

Write an algebraic expression for each of the following:

$3y-2=16(3,6,9,2)$

Answer 1

Given,Equation is $3y-2=16$

So, for $y=3$

We get, LHS$$\begin{gathered} =3\times 3-2 \\ =9-2 \\ =7 \end{gathered}$$

Now, LHS$\ne$RHS for $y=3$. So $y=3$ is not a solution for the equation $3y-2=16$.

So, for $y=6$

We get, LHS$$\begin{gathered} =3\times 6-2 \\ =18-2 \\ =16 \end{gathered}$$

Now, LHS$=$RHS for $y=6$. So $y=6$ is a solution for the equation $3y-2=16$.

So, for $y=9$

We get, LHS$$\begin{gathered} =3\times 9-2 \\ =27-2 \\ =25 \end{gathered}$$

Now, LHS$\ne$RHS for $y=9$. So $y=9$ is not a solution for the equation $3y-2=16$.

So, for $y=2$

We get, LHS$$\begin{gathered} =3\times 2-2 \\ =6-2 \\ =4 \end{gathered}$$

Now, LHS$\ne$RHS for $y=2$. So $y=2$ is not a solution for the equation $3y-2=16$.

Hence, $y=6$ is a solution for the equation $3y-2=16$.