Write an algebraic expression for the series 21, 32, 43, 54 … (taking n = 1, 2, and 3 … in order)

10n + 1

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10n + 10

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11n + 1

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11n + 10

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Solution

The correct option is D
11n + 10

Look at the numbers:
21 = 11 + 10 (21 = 11 x 1 + 10; taking n= 1)
32= 22 + 10 (32 = 11 x 2 + 10; taking n= 2)
43= 33 + 10 (43 = 11 x 3 + 10; taking n= 3)
54 = 44 +10 (54 = 11 x 4 + 1; taking n= 4)
All these numbers are obtained by multiplying natural numbers,'n' with 11 and adding 10 to the resulting product..
Therefore the algebraic expression for the given series is:
11n + 10, taking n = 1, 2, 3 in order.

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Similar questions

{n \in {1, 2, 3, . . ., 100} | (11)^{n} > (10)^{n} + (9)^{n}}

The given expression (11n + 10) is for numbers in a series (taking n = 1, 2, 3, 4…… in order).

Which of the following number belong to the given series.

If the given expression (11n + 1) is for numbers in a series (taking n = 1, 2, 3, 4…… in order).

Which of the following numbers does not belong to the given series?

Write an algebraic expression for the given series.

12, 23, 34, 45, ......

\frac{1}{10} + \frac{2}{10^{2}} + \frac{3}{10^{3}} + . . . . . . . . . + \frac{n}{10^{n}} + . . . . .

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