Write an equation of a line parallel to the x-axis, passing through the point $(3, 2)$ .

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Solution

$\begin{matrix} L e t e q^{h} o f l i n e y = m x + c W h i c h i s p a r a l l e l t o x - a x i s t h e n, a n d p a s s e s t h r o u g h t h e p o i n t (3, 2) \frac{d y}{d x} = 0 A s w e k n o w t h a t f r o m s h a p e f o r m u l a - (y - y_{1}) = \frac{d y}{d x} (x - x_{1}) (y - 2) = 0 (x - 3) y - 2 = 0 y = 2 u n i t . \end{matrix}$

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