Write an equivalent fraction of 45-54 with numerator 20

The H.C.F Of 45 and 54 is 9 so, we will divide its Nr and Dr by 9.45/54=45÷9/54÷90ex0ex =5/60ex0ex =5× 4/6× 40ex0ex=20/24Hence, the required fraction is ...

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Byju's Answer

Standard VI

Mathematics

Part of a Whole

Write an equi...

Question

Write an equivalent fraction of
$\frac{45}{54}$ with numerator $20$

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Solution

The H.C.F Of $45$ and $54$ is $9$ so,
we will divide its Nr and Dr by $9$ .
$\frac{45}{54} = \frac{45 \div 9}{54 \div 9} = \frac{5}{6} = \frac{5 \times 4}{6 \times 4} = \frac{20}{24}$

Hence, the required fraction is $\frac{20}{24}$

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Write an equivalent fraction of 4554 with numerator 20

The H.C.F Of 45 and 54 is 9 so, we will divide its Nr and Dr by 9.4554=45÷954÷9=56=5×46×4=2024Hence, the required fraction is 2024

Write an equivalent fraction of
$\frac{45}{54}$ with numerator $20$

The H.C.F Of $45$ and $54$ is $9$ so,
we will divide its Nr and Dr by $9$ .
$\frac{45}{54} = \frac{45 \div 9}{54 \div 9} = \frac{5}{6} = \frac{5 \times 4}{6 \times 4} = \frac{20}{24}$

Hence, the required fraction is $\frac{20}{24}$