Question

Write any four solutions for each of the following equations.
$3x+y=7$

Answer 1

Now,

$\begin{array}{c}3x+y=7\\ forx=0\\ 3\left(0\right)+y=7\\ \therefore y=7\\ fory=0\\ 3x+0=7\\ 3x=7\\ x=\frac{7}{3}\\ forx=1,\\ 3\left(1\right)+y=7\\ y=\frac{7}{3}\\ fory=1\\ 3x+1=7\\ 3x=6\\ x=\frac{6}{3}=2\end{array}$

So four solutions of the given equations are;

$\left(0,7\right)\left(\frac{7}{3},0\right)\left(1,\frac{7}{3}\right)\left(2,1\right)$