Question

Write balanced chemical equation for the following:
Action of dilute Sulphuric acid on Sodium sulphite.

Answer 1

Action of dilute Sulphuric acid on Sodium sulphite:-

1. When dilute Sulphuric acid reacts with Sodium sulphite, it gives Sodium sulphate, water and Sulphur dioxide.
2. Balanced chemical equation:- $\underset{(\mathrm{Sodium}\mathrm{sulphite})}{{\mathrm{Na}}_2{\mathrm{SO}}_3\left(\mathrm{s}\right)}+\underset{(\mathrm{Sulphuric}\mathrm{acid})}{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{dil}\right)\left(\mathrm{aq}\right)}\to \underset{(\mathrm{Sodium}\mathrm{sulphate})}{{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}+\underset{\left(\mathrm{Water}\right)}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}+\underset{(\mathrm{Sulphur}\mathrm{dioxide})}{{\mathrm{SO}}_2\left(\mathrm{g}\right)}$

Hence, Reaction of dilute Sulphuric acid with Sodium sulphite gives Sodium sulphate- $\underset{(\mathrm{Sodium}\mathrm{sulphite})}{{\mathrm{Na}}_2{\mathrm{SO}}_3\left(\mathrm{s}\right)}+\left(\mathrm{dil}\right)\underset{(\mathrm{Sulphuric}\mathrm{acid})}{{\mathrm{H}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}\to \underset{(\mathrm{Sodium}\mathrm{sulphate})}{{\mathrm{Na}}_2{\mathrm{SO}}_4\left(\mathrm{aq}\right)}+\underset{\left(\mathrm{Water}\right)}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}+\underset{(\mathrm{Sulphur}\mathrm{dioxide})}{{\mathrm{SO}}_2\left(\mathrm{g}\right)}$