1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Oxidation Number Method
Write balance...
Question
Write balanced chemical equations for the conversion of
C
r
O
2
−
4
to
C
r
2
O
2
−
7
in acidic medium and
C
r
2
O
2
−
7
to
C
r
O
2
−
4
in basic medium.
Open in App
Solution
In acidic medium, yellow chromate ion is converted into orange red dichromate ion.
2
C
r
O
2
−
4
Yellow
+
2
H
+
→
C
r
2
O
2
−
7
Orange-red
+
H
2
O
In alkaline medium, orange red dichromate ion is converted into yellow chromate ion.
C
r
2
O
2
−
7
Orange red
+
2
O
H
−
→
2
C
r
O
2
−
4
Yellow
+
H
2
O
Suggest Corrections
2
Similar questions
Q.
Balance the following chemical equation:
C
r
2
O
2
−
7
(
a
q
)
+
S
O
2
−
3
(
a
q
)
→
C
r
3
+
(
a
q
)
+
S
O
2
−
4
(
a
q
)
(Acidic medium)
Q.
The complete balanced equation in acid medium is:
H
2
S
O
3
+
C
r
2
O
2
−
7
→
H
2
S
O
4
+
C
r
3
+
+
H
2
O
Q.
For the reacton in an acidic medium :
C
2
H
5
O
H
+
C
r
2
O
2
−
7
→
C
H
3
C
O
O
H
+
C
r
3
+
Calculate the stoichiometric ratio of
C
2
H
5
O
H
to
C
r
2
O
2
−
7
when the reaction is balanced by oxidation number method
Q.
Balance the following redox reaction in basic medium:
C
l
O
−
+
C
r
O
−
2
→
C
l
−
+
C
r
O
2
−
4
Q.
Balance the following equation by ion electron method.
C
u
3
P
+
C
r
2
O
2
−
7
→
C
u
2
+
+
H
3
P
O
4
+
C
r
3
+
(acid medium).
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Balancing_oxidation number
CHEMISTRY
Watch in App
Explore more
Oxidation Number Method
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app