Question

Write balanced equation and name the product formed when cupric oxide reacts with nitric acid.

Answer 1

Reaction between cupric oxide and dilute nitric acid:

• When cupric oxide reacts with dilute nitric acid, it forms copper nitrate and water.
• The balanced chemical reaction can be represented as:

$\underset{}{\underset{\mathrm{Cupric}\mathrm{oxide}}{\mathrm{CuO}\left(\mathrm{s}\right)}}+\underset{}{\underset{\mathrm{Nitric}\mathrm{acid}}{2{\mathrm{HNO}}_3\left(\mathrm{l}\right)}}\to \underset{}{\underset{\mathrm{Copper}\mathrm{nitrate}}{\mathrm{Cu}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{s}\right)}}+\underset{}{\underset{\mathrm{Water}}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}}$