Write balanced equation for silver chloride reacts with ammonium hydroxide.

A g C l + N H_{4} O H \to [A g (N H_{3})_{2}] + 2 H_{2} O

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A g C l + 2 N H_{4} O H \to [A g (N H_{3})] + 2 H_{2} O

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A g C l + 2 N H_{4} O H \to [A g (N H_{3})_{2}] + 2 H_{2} O

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A g C l + 2 N H_{4} O H \to [A g (N H_{3})_{2}] + H_{2} O

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Solution

The correct option is C $A g C l + 2 N H_{4} O H \to [A g (N H_{3})_{2}] + 2 H_{2} O$
The balanced chemical equation for the reaction of silver chloride with $N H_{4} O H$ is as follows:
$A g C l + 2 N H_{4} O H \to [A g (N H_{3})_{2}] + 2 H_{2} O$
When silver chloride reacts with $N H_{4} O H$ , then there is formation of the complex, $[A g (N H_{3})_{2}]$ .

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Similar questions

[A g (N H_{3})_{2}] C l

A g^{+} + 2 N H_{3} ⇌ A g (N H_{3})_{2}^{+}; K_{1} = 1.7 \times 10^{7}

A g^{+} + C l^{-} ⇌ A g C l; K_{2} = 5.4 \times 10^{9}

A g C l + 2 N H_{3} ⇌ [A g (N H_{3})_{2}]^{+} + C l^{-}

A g^{+} + 2 N H_{3} ⇌ {[A g (N H_{3})_{2}]}_{3}^{+}

K_{1} = 1.7 \times 10^{7}

A g^{+} + C l^{-} ⇌ A g C l

K_{2} = 5.4 \times 10^{9}

A g C l + 2 N H_{3} ⇌ [A g (N H_{3})_{2}]^{+} C l^{-}

A g C l ↓ + 2 N H_{3} ⇌ [A g (N H_{3})_{2}]^{+} s o l u b l e + C l^{-}

\begin{matrix} A g C l ↓ & + & 2 N H_{3} & ⇌ & {[A g {(N H_{3})}_{2}]}^{+} & + & C l^{-} S o l u b l e \end{matrix}

A g C l

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