Write balanced net ionic equation for the following reaction in acidic solution.
$S_{4} O_{6}^{2 -} (a q) + A l (s) \to H_{2} S (a q) + A l^{3 +} (a q)$

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Solution

Given equation
$S_{4} O_{6}^{- 2} (a q) + A l (s) ⟶ H_{2} S (a q) + {A l}^{+ 3} (a q)$
By ion electron method,
In acidic solution (medium). The balanced reaction is
$S_{4} O_{2}^{- 6} + 2 A l + 12 H^{+} ⇌ 4 H_{2} S + 2 {A l}^{+ 3} + 2 H_{2} O$

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S_{2} O {_{6}}^{2 -} (a q) + C r_{2} O {_{7}}^{2 -} (a q) \to S_{4} O {_{6}}^{2 -} (a q) + C r^{3 +} (a q)

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S_{4} O_{6}^{2 -} (a q) + A l (s) \to H_{2} S (a q) + A l^{3 +} (a q)

S_{4} O_{6}^{2 -} (a q) + A l (s) \to H_{2} S (a q) + A l^{3 +} (a q)

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S_{4} O_{6}^{2 -} (a q) + A l (s) \to H_{2} S (a q) + A l^{3 +} (a q)

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