wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Write balanced net ionic equation for the following reactions in acidic solution.
S2O62(aq)+Cr2O72(aq)S4O62(aq)+Cr3+(aq)

A
6S2O62(aq)+Cr2O72(aq)+14H+3S4O62(aq)+2Cr3+(aq)+7H2O
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6S2O62(aq)+2Cr2O72(aq)+14H+3S4O62(aq)+2Cr3+(aq)+7H2O
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6S2O62(aq)+Cr2O72(aq)+14H+4S4O62(aq)+2Cr3+(aq)+7H2O
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 6S2O62(aq)+Cr2O72(aq)+14H+3S4O62(aq)+2Cr3+(aq)+7H2O
The unbalanced net ionic equation is S2O62(aq)+Cr2O72(aq)S4O62(aq)+Cr3+(aq)

Balance S atoms and Cr atoms
2S2O62(aq)+Cr2O72(aq)S4O62(aq)+2Cr3+(aq)

The oxidation number of Cr decreases from +6 to +3. Total decrease in the oxidation number for 2Cr atoms is 6.

To balance the decrease in the oxidation number with increase in the oxidation number, multiply sulphur species with 3.
6S2O62(aq)+Cr2O72(aq)3S4O62(aq)+2Cr3+(aq)

To balance O atoms, add 7 water molecules on RHS
6S2O62(aq)+Cr2O72(aq)3S4O62(aq)+2Cr3+(aq)+7H2O

To balance hydrogen atoms, add 14 protons on the LHS.
6S2O62(aq)+Cr2O72(aq)+14H+3S4O62(aq)+2Cr3+(aq)+7H2O

This is balanced chemical equation

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Balancing_oxidation number
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon