The correct option is
A 6S2O62−(aq)+Cr2O72−(aq)+14H+→3S4O62−(aq)+2Cr3+(aq)+7H2OThe unbalanced net ionic equation is S2O62−(aq)+Cr2O72−(aq)→S4O62−(aq)+Cr3+(aq)
Balance S atoms and Cr atoms
2S2O62−(aq)+Cr2O72−(aq)→S4O62−(aq)+2Cr3+(aq)
The oxidation number of Cr decreases from +6 to +3. Total decrease in the oxidation number for 2Cr atoms is 6.
To balance the decrease in the oxidation number with increase in the oxidation number, multiply sulphur species with 3.
6S2O62−(aq)+Cr2O72−(aq)→3S4O62−(aq)+2Cr3+(aq)
To balance O atoms, add 7 water molecules on RHS
6S2O62−(aq)+Cr2O72−(aq)→3S4O62−(aq)+2Cr3+(aq)+7H2O
To balance hydrogen atoms, add 14 protons on the LHS.
6S2O62−(aq)+Cr2O72−(aq)+14H+→3S4O62−(aq)+2Cr3+(aq)+7H2O
This is balanced chemical equation