Question

Write cubes of $5$ natural numbers which are multiples of $3$ and verify the following:
'The cube of natural number, which is a multiple of $3$ is a multiple of $27$.

Answer 1

${\left(3\right)}^3=3\times 3\times 3=27$
${\left(6\right)}^3=6\times 6\times 6=216$
${\left(9\right)}^3=9\times 9\times 9=729$
${\left(12\right)}^3=12\times 12\times 12=1728$
${\left(15\right)}^3=15\times 15\times 15=3375$
Verification:
${\left(3\right)}^3=27=27\times 1$
${\left(6\right)}^3=216=27\times 8$
${\left(9\right)}^3=729=27\times 27$
${\left(12\right)}^3=1729=27\times 64$
${\left(15\right)}^3=3375=27\times 125$
$\therefore$ 'The cube of natural number, which is a multiple of 3 is a multiple of 27'.