CameraIcon

SearchIcon

MyQuestionIcon

6

You visited us 6 times! Enjoying our articles? Unlock Full Access!

Solving Simultaneous Linear Equation Using Cramer's Rule

Write Dx fo...

Question

Write $D_{x}$ for the following simultaneous equations :
$3 x + 4 y = 8; x - 2 y = 5$

A

D_{x} = ∣ ∣ ∣ \begin{matrix} 6 & 4 5 & - 5 \end{matrix} ∣ ∣ ∣

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

D_{x} = ∣ ∣ ∣ \begin{matrix} 8 & 4 5 & - 2 \end{matrix} ∣ ∣ ∣

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

D_{x} = ∣ ∣ ∣ \begin{matrix} 2 & 6 9 & - 2 \end{matrix} ∣ ∣ ∣

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

D_{x} = ∣ ∣ ∣ \begin{matrix} 9 & 1 16 & - 1 \end{matrix} ∣ ∣ ∣

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $D_{x} = ∣ ∣ ∣ \begin{matrix} 8 & 4 5 & - 2 \end{matrix} ∣ ∣ ∣$
$D_{x}$ of two simulataenous linear equations $a_{1} x + b_{1} y = c_{1}$ and $a_{2} x + b_{2} y = c_{2}$
is given by $∣ ∣ ∣ \begin{matrix} c_{1} & b_{1} c_{2} & b_{2} \end{matrix} ∣ ∣ ∣$
Hence, for the given equations, $D_{x} = ∣ ∣ ∣ \begin{matrix} 8 & 4 5 & - 2 \end{matrix} ∣ ∣ ∣$

Suggest Corrections

thumbs-up

0

Similar questions

State the following statement is true or false

3 x + 4 y = 8; x - 2 y = 5

D_{x} = ∣ ∣ ∣ \begin{matrix} 8 & 4 5 & - 2 \end{matrix} ∣ ∣ ∣

Q. Write D_x for the following simultaneous equations :
(i) 3x + 4y = 8 ; x

-

2y = 5

(ii) 5x = 10

-

-

Q. For each of the differential equations, find the general solution:
1.

\frac{d y}{d x} + 2 y = sin x

\frac{d y}{d x} + 3 y = e^{- 2 x}

\frac{d y}{d x} + \frac{y}{x} = x^{2}

\frac{d y}{d x} + (sec x) y = tan x

(0 \leq x < \frac{π}{2})

{cos}^{2} x \frac{d y}{d x} + y = tan x

(0 \leq x < \frac{π}{2})

x \frac{d y}{d x} + 2 y = x^{2} log x

x log x \frac{d y}{d x} + y = \frac{2}{x} log x

(1 + x^{2}) d y + 2 x y d x = cot x d x

(x \neq 0)

x \frac{d y}{d x} + y - x + x y cot x = 0

(x \neq 0)

(x + y) \frac{d x}{d y} = 1

y d x + (x - y^{2}) d y = 0

(x + 3 y^{2}) \frac{d y}{d x} = y

(y > 0)

Q. Solve the following equations:

(2 y d x + 3 x d y) + 2 x y (3 y d x + 4 x d y) = 0

Q. Write the degree of the differential equation:

(\frac{d y}{d x})^{4} + 3 x \frac{d^{2} y}{d x^{2}} = 0

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Cramer's Rule

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Solving Simultaneous Linear Equation Using Cramer's Rule

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon