Write down an expression for the $n^{t h}$ term of this sequence:
$4, 10, 16, 22, 28$

4 n - 2

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6 n - 2

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5 n - 3

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5 n - 2

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Solution

The correct option is A $6 n - 2$
Given series:
$4, 10, 16, 22, 28, . . .$
$a = 4$
$d = 10 - 4 = 6$
We know,
$∴ t_{n} = a + (n - 1) d$
$= 4 + (n - 1) 6$
$= 6 n - 2$
Hence, the answer is $6 n - 2$ .

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