Question

Write down ten positive rational numbers such that numerator - denominator for each of them is $-2$. Write them in increasing order

Answer 1

Firstly, let us determine the numbers whose difference is $-2$ as follows:

$10-12,9-11,8-10,7-9,6-8,5-7,4-6,3-5,2-4$ and $1-3$

Now, the ten positive rational numbers in which the subtraction of the numerator and denominator is $-2$ are:

$\frac{10}{12},\frac{9}{11},\frac{8}{10},\frac{7}{9},\frac{6}{8},\frac{5}{7},\frac{4}{6},\frac{3}{5},\frac{2}{4},\frac{1}{3}$

Hence, the increasing order of the numbers is $\frac{1}{3},\frac{2}{4},\frac{3}{5},\frac{4}{6},\frac{5}{7},\frac{6}{8},\frac{7}{9},\frac{8}{10},\frac{9}{11},\frac{10}{12}$.