Write down the $6$ th term of the sequence whose $n$ th term is
$\frac{1}{n^{2}} sin (\frac{n π}{3})$

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Solution

$a_{n} = \frac{1}{n^{2}} sin (\frac{n π}{3})$

$a_{6} = \frac{1}{6^{2}} sin (\frac{6 π}{3}) = \frac{1}{6^{2}} sin (2 π) = 0$

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