Write down the four quantum number for $8 t h$ electron of oxygen atom?

n = 2, l = 1, m = + 2

- 2, s = + \frac{1}{2}

- \frac{1}{2}

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n = 2, l = 1, m = + 1

- 1, s = + \frac{1}{2}

- \frac{1}{2}

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n = 2, l = 1, m = 0, s = + \frac{1}{2}

- \frac{1}{2}

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n = 2, l = 0, m = 0, s = + \frac{1}{2}

- \frac{1}{2}

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Solution

The correct option is B $n = 2, l = 1, m = + 1$ or $- 1, s = + \frac{1}{2}$ or $- \frac{1}{2}$
The 8th electron in the oxygen atom belongs to 2p subshell.
For $8 t h$ electron of oxygen atom, the four quantum numbers are $n = 2, l = 1, m = + 1$ or $- 1, s = + \frac{1}{2}$ or $- \frac{1}{2}$ .

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Which set of quantum numbers is possible for the last electron of Mg⁺ ion?

n = 4, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{1} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 3, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 1, m_{1} = - 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

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