Write down the values of quantum numbers of all the electrons present in the outermost orbit of argon. (Atomic number $18$ ).

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Solution

Electronic configuration of Argon
${1 s}^{2} 2 s^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6}$
Last electrons quantum numbers
$I) {3 s}^{2} : n = 3, l = 0, m = 0, s = \frac{+ 1}{2}, \frac{- 1}{2} I I) 3 P_{x}^{2} : n = 3, l = 1, m = - 1, s = \frac{+ 1}{2}, \frac{- 1}{2} I I I) 3 P_{y}^{2} : n = 3, l = 1, m = 0, s = \frac{+ 1}{2}, \frac{- 1}{2} I V) 3 P_{z}^{2} : n = 3, l = 1, m = 1, s = \frac{+ 1}{2}, \frac{- 1}{2}$

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