Write dual of - -p- q-p-q- r-

The correct option is A ∼ p∧∼ q∧[p∨∼ q∨ r)] Dual ⇒ ' ∨ ' is replaced by ' ∧ ' #160; #160; #160; #160; #160; #160; #160; ...

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Negation

Write dual of...

Question

Write dual of :
$\sim (p \land q) \lor [p \land \sim (q \lor \sim r)]$

(p \land q) \lor [p \land \sim (q \lor \sim r)]

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\sim (p \land q) \lor [p \land \sim (q \lor \sim r)]

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\sim p \land \sim q \land [p \lor \sim q \lor r)]

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\sim p \lor \sim q \land [p \land \sim q \land r)]

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The dual of statement $p \lor (q \land r) \equiv (p \lor q) \land (p \lor r)$ is

Factorise: $(p^{2} + q^{2} - r^{2})^{2} - 4 p^{2} q^{2}$

p \land [\sim q \lor (p \land q) \lor \sim r]

(p - q)^{3} + (q - r)^{3} + (r - p)^{3}

The contrapositive of $(\sim p \land q) \to (q \land \sim r)$ is

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