Question

Write electronic configurations of the Boron.

Answer 1

Boron is the fifth element with a total of $5$ electrons. In writing the electron configuration for Boron the first two electrons will go in the $1s$ orbital. Since $1s,$ can only hold two electrons the next 2 electrons for B goes in the $2s$ orbital. The remaining electron will go in the $2p$ orbital.

The electronic configuration of Boron: $1s^{2}2s^{2}2p^1$