Question

Write electronic configurations of the elements (number in the brackets indicate atomic numbers)
nitrogen $\left(7\right)$

Answer 1

Nitrogen is the seventh element with a total of 7 electrons. In writing the electron configuration for nitrogen the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for N goes in the $2s$ orbital. The remaining three electrons will go in the 2p orbital. Therefore the N electron configuration will be $1s^{2}2s^{2}2p^3$