Question

Write equations for the reactions of aqueous hydrochloric acid on Zinc carbonate

Answer 1

The reaction of Zinc Carbonate ($ZnC{O}_3$) with dilute Hydrochloric acid ($HCl$) yields Zinc chloride ($ZnC{l}_2$), water ($H_{2}O$) and results in the release of Carbon dioxide ($C{O}_2$).

The reaction is as follows:

$ZnC{O}_3\left(s\right)+HCl\left(aq\right)\to ZnC{l}_2\left(s\right)+H_{2}O\left(l\right)+C{O}_2\left(g\right)\uparrow$

The reaction can be balanced by balancing the number of chlorine and hydrogen atoms. We can write $2$ before $HCl$.

$ZnC{O}_3\left(s\right)+2HCl\left(aq\right)\to ZnC{l}_2\left(s\right)+H_{2}O\left(l\right)+C{O}_2\left(g\right)\uparrow$